Timeline for Median of a Vector assignment
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Feb 12, 2022 at 23:34 | history | edited | Toby Speight |
edited tags
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| Oct 30, 2018 at 22:45 | vote | accept | Ulivax | ||
| Oct 30, 2018 at 6:55 | answer | added | Snowhawk | timeline score: 4 | |
| Oct 30, 2018 at 0:30 | comment | added | papagaga | Printing is an idea but I feel like it's not pertinent here. You should be able to use the median after computing it. At this point, you could consider that the problem wasn't well thought out in the first place, or consider that certain inputs are invalid (empty vector, or uniform, even-sized vector) and ask for another one. | |
| Oct 30, 2018 at 0:20 | comment | added | Ulivax | I was thinking about that and the only method I could think of was to print the vector and in the middle show the median value between the exact number of elements adjacent to computed value. | |
| Oct 30, 2018 at 0:17 | comment | added | papagaga | besides you can't solve the problem in certain cases, such as a vector of even size filled with only one number ( [2,2,2,2] for instance): there's is no number such as "exactly as many elements come before it in the sequence as come after it". So what will you do about it? | |
| Oct 30, 2018 at 0:13 | comment | added | papagaga |
you need to take of the case where temps.size() == 0, because it fits the temps.size() % 2 == 0 but then temps[temps.size() / 2 - 1] will backfire
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| Oct 29, 2018 at 22:12 | history | edited | 200_success | CC BY-SA 4.0 |
added 22 characters in body; edited tags
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| Oct 29, 2018 at 22:01 | history | asked | Ulivax | CC BY-SA 4.0 |