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Jan 10, 2019 at 16:01 answer added Aweuzegaga timeline score: 2
Oct 4, 2018 at 20:56 comment added Ralf Kleberhoff One small hint regarding the new HashMap<>(8): in your case, it's not worth deciding on an initial capacity. And if you really care, you should start with a bigger capacity, as a new HashMap<>(8) will not accept 8 entries without growth, but only 6. The default load factor is 75%, meaning that the HashMap will grow as soon as it's 75% filled.
Oct 4, 2018 at 7:43 comment added Toby Speight The number of outputs will be 3^n or more (not n^3), so that's obviously a lower bound on the complexity. You won't be able to get lower than that without omitting some of the results.
Oct 4, 2018 at 7:26 answer added Sharon Ben Asher timeline score: 3
Oct 4, 2018 at 6:30 history edited 200_success CC BY-SA 4.0
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Oct 4, 2018 at 4:40 review First posts
Oct 4, 2018 at 7:45
Oct 4, 2018 at 4:38 history asked dragons CC BY-SA 4.0