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Oct 13, 2017 at 5:32 comment added Rocket Pingu Either way, you'd have to check if the input is valid twice: one for inside the loop; one for the loop condition just like the accepted answer.
Oct 13, 2017 at 5:24 comment added 200_success while(isInvalid(input)) is very clumsy. Not only do you artificially initialize input to an invalid value to force it to enter the loop the first time, you also have a redundant isInvalid(input) rest inside the loop. You would be better off with a do-while loop.
Oct 13, 2017 at 4:06 history edited Rocket Pingu CC BY-SA 3.0
Fixed code.
Oct 13, 2017 at 3:52 comment added Rocket Pingu Oh wait, I didn't see that part. Lemme rework my code.
Oct 13, 2017 at 3:44 comment added Gerrit0 Your reworked code abandons the error handling the OP includes presumably for good reason. This probably isn't a good idea.
Oct 13, 2017 at 3:39 history answered Rocket Pingu CC BY-SA 3.0