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Oct 18, 2012 at 14:11 history edited zdd CC BY-SA 3.0
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Oct 18, 2012 at 14:03 comment added zdd Yes, you are right, the solution won't work if a or b is 1001, may be we can use a list to store a key-value pair where the key is the factor and the value is the times of that factor, but that will make the code more complexity, I like simple code :)
Oct 18, 2012 at 14:00 comment added Adil Mughal I like your approach. The only thing we would lose its extra space...int[1000]. Plus few queries: -Is 1000 definite? - for (int m = 0; m < factorsA.Length; ++m) would that work if factorsB length is greater than factorsA ?
Oct 18, 2012 at 13:57 review First posts
Oct 18, 2012 at 15:25
Oct 18, 2012 at 13:55 history answered zdd CC BY-SA 3.0