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Nov 15, 2019 at 9:38 vote accept Daniele
May 5, 2016 at 10:19 comment added Daniele @Flambino I know there is URL parsing in Node, but if you read the code you will notice that my requirement is a little far from parsing the url, I need to exctract specific values separated in different ways
May 5, 2016 at 3:41 history edited Jamal CC BY-SA 3.0
deleted 1 character in body; edited title
May 5, 2016 at 3:17 answer added Laurel timeline score: 2
S Apr 20, 2016 at 14:24 history bounty ended CommunityBot
S Apr 20, 2016 at 14:24 history notice removed CommunityBot
Apr 12, 2016 at 20:33 history edited 200_success
edited tags
S Apr 12, 2016 at 20:28 history edited Sjoerd Job Postmus CC BY-SA 3.0
improved formatting of URL.
Apr 12, 2016 at 20:24 review Suggested edits
S Apr 12, 2016 at 20:28
Apr 12, 2016 at 15:33 comment added Flambino Even without npm, there's URL parsing built into Node already, so there's no need to roll your own
Apr 12, 2016 at 14:16 comment added Zack Have you looked into a library to do this? It seems like it would be more effective than reinventing your own. I found gist.github.com/jlong/2428561 and npmjs.com/package/url-parse in the first few search results. Even if you can't use them, you can look over the code base and see if anything can be used with what you have. The second link specifically mentions a RegEx engine.
S Apr 12, 2016 at 12:47 history bounty started Daniele
S Apr 12, 2016 at 12:47 history notice added Daniele Draw attention
S Apr 7, 2016 at 13:01 history edited BCdotWEB CC BY-SA 3.0
fixed a typo
S Apr 7, 2016 at 13:01 history suggested José Castro CC BY-SA 3.0
fixed a typo
Apr 7, 2016 at 12:57 review Suggested edits
S Apr 7, 2016 at 13:01
Apr 6, 2016 at 7:11 comment added michael.zech The line "const path_matcher = /(?:([^\/\/]+))/g;" : Wouldn't have '/(?:([^\/]+))/g' the same result. You add the slash ( / ) two times to your set of not allowed characters. The second time isn't necessary. At least I guess so? I can be wrong ...
Apr 5, 2016 at 9:34 history asked Daniele CC BY-SA 3.0