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public static int lastDigit(int a) {
    a = a % 10;
    if (a <= 0){
    a *= -1;
    }
    return a;
}

This is my solution. The course hasn't taught if else yet, so I'm wondering if there is a way to do it without the if else.

public static int lastDigit(int a) {
a = a % 10;
return a;
}

The problem with this is that it will not print the last digit of a negative number as a negative.

public static int lastDigit(int a) {
    a = a % 10;
    if (a <= 0){
    a *= -1;
    }
    return a;
}

This is my solution. The course hasn't taught if else yet, so I'm wondering if there is a way to do it without the if else.

public static int lastDigit(int a) {
a = a % 10;
return a;
}

The problem with this is that it will not print the last digit of a negative number as a positive.

public static int lastDigit(int a) {
if (a >= 0){
a = a % 10;
return a;
}
else {
a = a % 10;
return (a * -1);
}}

This is my solution. The course hasn't taught if else yet, so I'm wondering if there is a way to do it without the if else.

public static int lastDigit(int a) {
a = a % 10;
return a;
}

The problem with this is that it will not print the last digit of a negative number as a negative.

public static int lastDigit(int a) {
    a = a % 10;
    if (a <= 0){
    a *= -1;
    }
    return a;
}

This is my solution. The course hasn't taught if else yet, so I'm wondering if there is a way to do it without the if else.

public static int lastDigit(int a) {
a = a % 10;
return a;
}

The problem with this is that it will not print the last digit of a negative number as a negative.