Generating a range of ints as strings in Java 8

Question

I'll have two integers and will want to generate an array of those two numbers and all the numbers in between as strings (I know the ranges are small).

i.e. given 1004 and 1008. I'd generate "1004", "1005", "1006", "1007", "1008"

I'm familiar with C# and there I'd do something like

var start = 1004;
var end = 1008;
var fullRange = Enumerable.Range(start, end - start + 1)
                          .Select(i => i.ToString())
                          .ToArray();

I need to do this in Java 8 and have come up with

 String[] fullRange = IntStream.range(start, end+1)
                        .mapToObj(String::valueOf)
                        .toArray(String[]::new);

But I'm new to Java and wondered if there's a better / more-readable way to achieve this in Java. Am I just cramming C# into Java?

Answer 1

Can you use a stream rather than an array in the rest of your application? If so I'd simply cut off the toArray bit at the end. Otherwise this looks exactly like what I'd expect in Java 8.

Answer 2

IntStream has a rangeClosed method that allows you to omit the +1.

IntStream.rangeClosed(start, end) instead of IntStream.range(start, end+1)