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I'd like some tips on optimizing the following code.

I'm a bit concerned that I'm 'polluting the global namespace' by not wrapping it in a function. The commented out var rotator { init { came from a JavaScript tutorial but I'm not sure it's the jQuery way? Should I wrap it in $(function()... instead?

$(document).ready(function() {

//Promos rotation
var $accordionList = $('.accordion').find('li');

// var rotator = {
//      init: function() {
        var numberOfItems = $accordionList.length;
        var currentItem = 0;

        // Set first item to active
        $accordionList.eq(currentItem).addClass('active').find('.content').slideToggle(800, function() {});
        var infiniateLoop = setInterval(function() {
            if(currentItem == numberOfItems - 1){
                currentItem = 0;
            else {

            // Remove active class, if is has it, and close content
                .find('.content').slideToggle(800, function() {

            // Add active class and open content
            $accordionList.eq(currentItem).addClass('active').find('.content').slideToggle(800, function() {

        }, 4000 );

        //$('.accordion li').on('click', function () {
        $accordionList.on('click', function () {
            // Stop rotation

            var $accordionHead = $(this);

            // Remove active class, if is has it, and close content
                .find('.content').slideToggle(800, function() {

            // Add active class and open content
            $accordionHead.addClass('active').find('.content').slideToggle(800, function() {
//      }
// };

// rotator.init();

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migrated from Dec 5 '12 at 13:42

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"I'm not sure it's the JQuery way?" jQuery way? $(function(){}) === $(document).ready(function(){}) – Raminson Dec 5 '12 at 10:54
you are wrapping it in a function... $(document.ready(function... – ahren Dec 5 '12 at 10:56
Your code as it is does not polute any global namespace, as it's all contained within a function being called by $(document).ready. The addition or removal of the rotator object does not change this fact. Either way it's wholey contained within a function – Jamiec Dec 5 '12 at 10:56
Since you wrapped your code in $(document).ready() and you are using the var keyword you are surely not polluting the global namespace – devnull69 Dec 5 '12 at 10:56
yes but shouldn't I wrap it in another function so it doesn't conflict with other fucntion (yet to be written) that are also in the document.ready ? – Chris Dec 5 '12 at 10:57

To your question ( confirmed by the comments ), you are not polluting the namespace because you are

  1. Wrapping already inside $(document).ready(function() {
  2. Using var for every variable.

Furthermore, from what I can see that is left over from rotator, it was probably a better approach than what you have now.

From a once over:

  • Spelling is important: infiniateLoop -> infiniteLoop
  • slideToggle(800, function() {}); can simply be written as slideToggle(800);
  • You could use a ternary for increasing currenItem : currentItem = currentItem == numberOfItems - 1 ? 0 : ++currentItem;
  • Please remove commented out code, also please re-indent after taking out rotator
  • It is considered good practice to have one big var at the start instead of multiple vars:
var $accordionList = $('.accordion').find('li'),
    numberOfItems = $accordionList.length,
    currentItem = 0;

    // Set first item to active
  • Jshint could not find a single flaw
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