Stripping a String from a String [closed]

Question

Ok. So on this page I have the data being pulled in using the SourceQuery class but when I get the hostname there is extra data that I don't want on the page.

This is the page: http://almost-there.org/beta.php

This is the code that I am using.

$SName = $StatsTF["HostName"];
$SName = str_replace("Almost There | ", "", $SName);

The full string that it returns is: "Almost-There | Stock Maps #1 | East Coast (x24)"

The end result I am trying to get to is: "Stock Maps #1 | East Coast (x24)"

Am I right in using str_replace or should I be using another function?
If I should be str_replace then what am I doing wrong?

Answer 1

You are trying to replace the string "Almost There" when you should be trying to replace the string "Almost-There". Seems you are missing the dash between the words.

Edit: Looking at the hostname on the page, it seems that the original hostname doesn't even have a dash between the two words, so I don't know what's going on there. Alternatively you could try using substr on the hostname variable to cut off the correct number of characters you don't require. Something like:

$SName = substr($SName, 15);

Answer 2

This is a slight improvement:

$SName = str_replace('Almost-There | ', '', $StatsTF['HostName']);

1. Double quotes "", PHP parses the string for variables, single quotes '', PHP doesn't parse the string.
2. There's no reason to store the variable $SName and then process it. Just get and process it in one fell swoop.

Answer 3

Looking at the code, I can't see anything that would lead to str_replace not working. The only thing I can see that might trip it up would be the pipe (|). It might be using the pipe as a preg match; try using single quotes instead of double:

$SName = str_replace('Almost There | ', '', $SName);

Or escaping the pipe, "Almost There \| " ...

I could be wrong on both accounts (my PHP is about a year old :/) but you're using str_replace correctly.