How do I map a Map<String, Integer> on JPA [closed]

Question

@MappedSuperclass
public class ClientBase implements Client, Serializable {

    @Id @GeneratedValue
    private Long id;
    private String userName;
    private String password;
    private Map<String, Integer> permissions;
    private String name;
    @Temporal(javax.persistence.TemporalType.DATE)
    private Date birthday;
    private Adress adress;
    private Contact contact;
 ...

Answer 1

You should use @ManyToMany(cascade = CascadeType.ALL). Please, take a look here and here for details.